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  1. Grade 12 Mathematics/

Polynomials

Polynomials: Beyond the Parabola (~15 marks, Paper 1)
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In Grade 12, we learn to handle functions with powers higher than 2 (like $x^3$). Polynomial questions appear in Paper 1 under Algebra (~25 marks) and are also essential for the Calculus section (sketching cubic graphs).


The Key Idea: Factors = Roots = $x$-intercepts
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Finding the factors of a polynomial is the same as finding the $x$-intercepts of the graph:

  • If $(x - 2)$ is a factor of $f(x)$, then $f(2) = 0$, and the graph crosses the $x$-axis at $x = 2$.
  • This connection is what makes the Factor Theorem so powerful.

The Two Theorems
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TheoremStatementUse
Remainder TheoremIf $f(x)$ is divided by $(x - a)$, the remainder is $f(a)$Quick way to find remainders without dividing
Factor Theorem$(x - a)$ is a factor of $f(x)$ if and only if $f(a) = 0$Testing whether a value is a root

How to Use the Factor Theorem
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To factorise $f(x) = x^3 - 7x - 6$:

  1. Try values: Test $f(1)$, $f(-1)$, $f(2)$, $f(-2)$, $f(3)$, $f(-3)$, $f(6)$, $f(-6)$…
  2. Find a root: $f(-1) = -1 + 7 - 6 = 0$ ✓ → so $(x + 1)$ is a factor
  3. Divide: Use long division or synthetic division to get the quadratic quotient
  4. Factorise the quadratic: $x^3 - 7x - 6 = (x + 1)(x^2 - x - 6) = (x + 1)(x - 3)(x + 2)$

💡 Which values to try: Always try the factors of the constant term ($\pm 1, \pm 2, \pm 3, \pm 6$ for $-6$). One of these will be a root.


Synthetic Division (The Quick Method)
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For dividing $f(x)$ by $(x - a)$:

  1. Write down the coefficients of $f(x)$
  2. Bring down the first coefficient
  3. Multiply by $a$, add to the next coefficient, repeat
  4. The last number is the remainder

This is faster than long division and less error-prone.


Deep Dives (click into each)
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🚨 Common Mistakes
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  1. Not trying enough values: If $f(1) \neq 0$, try $f(-1)$, $f(2)$, etc. Be systematic — try all factors of the constant term.
  2. Division errors: In long division, make sure you account for “missing” terms. If $f(x) = x^3 + 2x - 5$, write it as $x^3 + 0x^2 + 2x - 5$ (include the $0x^2$ placeholder).
  3. Forgetting to factorise the quadratic: After finding the first factor and dividing, you get a quadratic — you must still factorise (or use the formula on) that quadratic.
  4. Sign errors in the Factor Theorem: $(x + 1)$ is a factor means $f(-1) = 0$, NOT $f(1) = 0$. The sign flips!
  5. Not linking to graphs: If a question asks for the $x$-intercepts of a cubic, you’re really being asked to factorise and solve $f(x) = 0$.

🔗 Related topics:

  • Differential Calculus — factorising cubics is essential for finding $x$-intercepts when sketching cubic graphs
  • Algebra — cubic equations appear in Question 1 of Paper 1

📌 Grade 10 foundation: Factorisation — the factoring toolkit you must know before tackling cubics


⏮️ Finance, Growth & Decay | 🏠 Back to Grade 12 | ⏭️ Differential Calculus

Remainder & Factor Theorems

Master the Remainder and Factor Theorems from first principles — understand why they work, how to use them to test factors, find remainders, and solve for unknowns with fully worked examples.